CBSE Sample paper 11- IX - Math -SA II Solutions 1]

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The chord which passes through the centre of the circle, is called a Diameter of the circle.

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On the line y = 0, for all values of x, value of y is always zero.

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Put x = 0 and y = 0 in the equation we get the right side of the equation equals to 0. So, (0, 0) is a solution of the equation 2x + 5y = 0 (1 Mark)

(1 Mark)

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The given line is parallel to the Y axis, therefore its equation is of the type x = a.(1 Mark) Now, the line passes through the point (1, 0). This implies that a = 1. Hence the equation of the line is x = 1 (1 Mark)

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Let the age of the son 3 years back be x years Therefore, the age of the father 3 years back was x + 24

(1 Mark)

At present the age of the son is x + 3 and the father is 5 times as old as the son. i.e., x + 24 + 3 = 5(x + 3) (1 Mark) i.e., x + 27 = 5x + 15 or 4x = 12 or x = 3.(1 Mark) Therefore, the son was 3 years old 3 years back and he will be 9 years old three years from now. (1 Mark)

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The chord which passes through the centre of the circle, is called a Diameter of the circle.

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7]

On the line y = 0, for all values of x, value of y is always zero.

8]

Put x = 0 and y = 0 in the equation we get the right side of the equation equals to 0. So, (0, 0) is a solution of the equation 2x + 5y = 0 (1 Mark)

(1 Mark)

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The given line is parallel to the Y axis, therefore its equation is of the type x = a.(1 Mark) Now, the line passes through the point (1, 0). This implies that a = 1. Hence the equation of the line is x = 1 (1 Mark)

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Let the age of the son 3 years back be x years Therefore, the age of the father 3 years back was x + 24

(1 Mark)

At present the age of the son is x + 3 and the father is 5 times as old as the son. i.e., x + 24 + 3 = 5(x + 3) (1 Mark) i.e., x + 27 = 5x + 15 or 4x = 12 or x = 3.(1 Mark) Therefore, the son was 3 years old 3 years back and he will be 9 years old three years from now. (1 Mark)

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