Practice Placement Exam. ANSWERS. There are 20 questions. Try your best
without notes, books, or calculators. The placement exam for. MTH111
Precalculus ...
MTH 111: PreCalculus
Practice Placement Exam Practice Placement Exam ANSWERS
There are 20 questions. Try your best without notes, books, or calculators. The placement exam for MTH111 Precalculus consists of Basic Algebra and College Algebra questions. See the course website for solutions to the practice placement exam. The actual placement exam for MTH111 is given during the first week of classes and is a multiple choice exam. You need a passing score to meet the prerequisite requirement for MTH111 Precalculus. See the MTH111 course website for details on the placement exam.
ANSWERS
1. Find the numerical value of 5 − 7(2 − 8). Ans: 5 − 7(2 − 8) = 5 − 7(−6) = 5 + 42 = 47 47
2. If 2x − 7 = 9 − 6x. Then x = Ans: 2x − 7 +6x 8x − 7 +7 8x 8
= 9 − 6x = +6x = 9 = +7 =
16 8
x = 2 x=2
4 2 3. Find the value of the exponential expression: 3 Ans: 4 2 24 2·2·2·2 16 = 4 = = 3 3 3·3·3·3 81 16 81
13. Solve the absolute value equation |2x + 3| + 9 = 16 Ans: |2x + 3| + 9
=
16
−9
=
−9
|2x + 3|
=
7 (
2x + 3
=
−7 (
2x + 3 − 3
=
2x ·
=
=
4·
1 2
−10 · (
x
7−3
−7 − 3 (
1 2
7
1 2
2 −5
Check x = 2 in the original equation |2x + 3| + 9 = 16 to make sure it is a solution. Check x = −5 in the original equation |2x + 3| + 9 = 16 to make sure it is a solution. Both x = 2 and x = −5 are solutions
17. P is the point (−2, 1) and Q is the point (3, 4). What is the slope of the line connecting the points? Ans: (x1 , y1 ) = (−2, 1) (x2 , y2 ) = (3, 4) Slope: m=
4−1 y2 − y1 4−1 3 = = = x2 − x1 3 − −2 3+2 5
Slope is
3 5
18. Solve the equation for x: Ans: 2 1 − x 3 2 1 1 − + x 3 3 2 x 2 x 2 x· x 15 2· 11 30 11 x=
19. If x = −4, what is the value of 2x2 − 3x + 7? Ans: 2(−4)2 − 3(−4) + 7 = 2 · 16 + 12 + 7 = 32 + 12 + 7 = 51 51
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20. Given two points (−1, 3) and (2, 5) find the equation of the line that goes through the points. Ans: (x1 , y1 ) = (−1, 3) (x2 , y2 ) = (2, 5) Slope: m=
y2 − y1 5−3 5−3 2 = = = x2 − x1 2 − −1 2+1 3
Equation of a line: (y − y1 ) = m(x − x1 ) (y − 3)