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Answers to NCERT/CBSE MATHEMATICS Class 10(Class XI)textbook ... The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find.
NCERT/CBSE MATHEMATICS CLASS 10 textbook(OPTIONAL EXERCISE) http://www.TutorBreeze.com Contact for Online Tutoring in Physics, Math, Chemistry, English Answers to NCERT/CBSE MATHEMATICS Class 10(Class XI)textbook OPTIONAL EXERCISE CHAPTER FIVE

ARITHMETIC PROGRESSION EXERCISES

2. The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP.

Solution: We know that the n th term of an Arithmetic Progression, whose First term = a and Common Difference = d is given by

(n - 1 ) d ∴ a3 = a + (3 - 1 ) d = a + 2 d a 7 = a + ( 7 - 1 ) d = a + 6d an = a +

The sum of the third and the seventh terms of an AP is 6 ⇒ a 3 + a 7 = ( a + 2 d ) + ( a + 6d ) = 6 ⇒ 2 a + 8d = 6 ⇒ a + 4d = 3 ⇒ a = 3 − 4d and the product of the third and the seventh terms of that AP is 8. ⇒ a 3 × a 7 = ( a + 2 d ) × ( a + 6d ) = 8 ⇒ ( a + 2 d ) × ( a + 6d ) = 8 ⇒ ( 3 − 4d + 2 d ) × ( 3 − 4d + 6d ) = 8 ⇒ ( 3 − 2d ) × ( 3 + 2d ) = 8 ⇒ 9 − 4d 2 = 8 ⇒ 4d 2 = 9 − 8 = 1

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NCERT/CBSE MATHEMATICS CLASS 10 textbook(OPTIONAL EXERCISE) http://www.TutorBreeze.com

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1 4 1 ⇒d =± 2 1 1 d = ⇒ a = 1 and d = − ⇒ a = 5 2 2 Now to Find the sum of first sixteen terms of the AP: ⇒ d2 =

We know that the sum of n terms of an AP whose First Term = a and Common Difference = d is given by n Sn = [ 2a + (n − 1)d ] 2 16 ⇒ S16 = [ 2a + (16 − 1)d ] = 8 [ 2a + 15d ] 2 1 Whend = ; a = 1 2 1 19   15  S16 = 8 [ 2a + 15d ] = 8  2.1 + 15.  = 8  2 +  = 8. = 76 2 2 2   1 Whend = − ; a = 5 2  15  5  1   S16 = 8 [ 2a + 15d ] = 8  2.5 + 15.  −   = 8 10 −  = 8. = 20 2 2  2   

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