On (m, n)-ideals and (m, n)-regular ordered semigroups

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concepts of (m, n)-ideals and (m, n)-regularity of ordered semigroups introduced and studied by Sanboorisoot et al. (2012), we extend the results obtained by ...
Songklanakarin J. Sci. Technol. 38 (2), 199-206, Mar. - Apr. 2016 http://www.sjst.psu.ac.th

Original Article

On (m, n)-ideals and (m, n)-regular ordered semigroups Limpapat Bussaban* and Thawhat Changphas Department of Mathematics, Faculty of Science, Khon Kaen University, Mueang, Khon Kaen, 40002 Thailand. Received, 1 July 2015; Accepted, 13 October 2015

Abstract Let m, n be non-negative integers. A subsemigroup A of an ordered semigroup (S,  ,  is called an (m, n)-ideal of S if (i) AmSAn  A, and (ii) if x  A, y  S such that y  x, then y  A. In this paper, necessary and sufficient conditions for every (m, n)-ideal (resp. (m, n)-quasi-ideal) of an (m, n)-ideal (resp. (m, n)-quasi-ideal) A of S is an (m, n)-ideal (resp. (m, n)-quasiideal) of S will be given. Moreover, (m, n)-regularity of S will be discussed. The results obtained extend the results on semigroups (without order) studied by Bogdanovic (1979). Keywords: semigroup, ordered semigroup, (m, n)-ideal, (m, n)-quasi-ideal, (m, n)-regular

1. Preliminaries Let m, n be non-negative integers. A subsemigroup A of a semigroup S is called an (m, n)-ideal of S if m

n

A SA  A. Here, A0S = SA0 = S. This notion was first introduced and studied by Lajos (1961). Furthermore, the theory of (m, n)-ideals in other structures have also been studied by many authors (see also Akram et al., 2013; Amjad et al., 2014; Lajos, 1963; Yaqoob et al., 2012; Yaqoob et al., 2013; Yaqoob et al., 2014; Yousafzai et al., 2014). A semigroup S is said to be (m, n)-regular (Krgovic, 1975) if for any a in S, there exists x in S such that a  a m xa n . Bogdanovic (1979) studied some properties of (m, n)-ideals and (m, n)-regularity of S. Indeed, the author characterized when every (m, n)-ideal of an (m, n)-ideal A of S is an (m, n)-ideal of S. Moreover, (m, n)regularity of S was discussed. In this paper, using the concepts of (m, n)-ideals and (m, n)-regularity of ordered semigroups introduced and studied by Sanboorisoot et al. (2012), we extend the results obtained by Bogdanovic (1979) mentioned above to ordered semigroups.

* Corresponding author. Email address: [email protected], [email protected]

A semigroup ( S , ) together with a partial order  that is compatible with the semigroup operation, meaning that, for any a, b, c in S,

a  b  ac  bc, ca  cb, is said to be an ordered semigroup (Birkhoff, 1967; Fuchs, 1963). A non-empty subset A of an ordered semigroup ( S , , ) is said to be a subsemigroup of S if ab  A for all a, b in A (Kehayopulu, 2006). If A and B are non-empty subsets of an ordered semigroup ( S , , ), the set product AB is defined to be the set of all elements ab  S such that a  A and b  B , that is, AB  {ab ∣a  A, b  B} . And, we write

( A]  {x  S ∣x  a for some a  A}. It is observed by Kehayopulu (2006) that the following conditions hold: (1) A  ( A] ; (2) ( A]( B ]  ( AB ] ; (3) If A  B , then ( A]  ( B] ; (4) ( A  B]  ( A]  ( B ]; (5) ( A  B ]  ( A]  ( B ] . A non-empty subset A of an ordered semigroup ( S , , ) is called a left (resp. right) ideal of S if it satisfies the following conditions: (i) SA  A (resp. AS  A ); (ii) ( A]  A. And, A is called a two-sided ideal (or simply an ideal) of S if it is both a left and a right ideal of S (Kehayopulu, 2006). A subsemigroup B of S is called a bi-ideal of S if (i) BSB  B ; (ii) ( B]  B (Kehayopulu, 1992). A non-

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L. Bussaban & T. Changphas / Songklanakarin J. Sci. Technol. 38 (2), 199-206, 2016

empty subset Q of S is called a quasi-ideal of S if (i) (QS ]  ( SQ]  Q ; (ii) (Q ]  Q (Tsingelis, 1991; Kehayopulu, 1994). Note that if Q is a quasi-ideal of S, then it is a subsemigroup of S. In fact, if Q is a quasi-ideal of S, then QQ  (QS ]  ( SQ]  Q . Finally, a subsemigroup A of S is called an (m, n)-ideal of S (m, n are non-negative integers) m n if (i) A SA  A ; (ii) ( A]  A (Sanborisoot et al., 2012). We first prove the following theorem.

mn

S ((  Ai  Am SAn ])n  ( SAn ]. i 1

Then, mn

((  A  A i



ing A of S. Then Ai is a subsemigroup containing A of iI S. For j  I , we have

] 

it follows that



mn i 1

i I

i I

( Ai ] 



i I

Ai 

(

i I

]

Ai ,

m

SAn ]  (([ A]( m, n ) ) m S ([ A]( m , n ) ) n ]  [ A]( m , n ) ,

mn

( A  A i

m

SAn ]  [ A]( m , n ) .

i 1

Ai is an (m, n)-ideal of S.

i

A  Am SAn ] is a subsemigroup of S. We now

This completes the proof.  For an element a of an ordered semigroup ( S , , ) , we write [{a}]( m , n ) (or simply [ a ]( m , n ) ) by: mn

consider:

[ a ]( m , n )  (  {a}i  a m Sa n ] .

mn

(( A  A i

m

i 1

SAn ]) m S

i 1 mn

m n

i 1

i 1

 ((  Ai  Am SAn ])m 1 ( Ai  Am SAn ]S m n

 ((  Ai  Am SAn ])m 1 ( AS ] m n

 (( A  A SA i

i 1

mn

m

(ii) (Q ]  Q .

m n

n

]) ( A m 2

i

 A SA ]( AS ]

i 1

 ((  Ai  Am SAn ]) m  2 ( A2 S ] i 1



 ( Am S ].

To extend the notion of (m, n)-quasi-ideals of semigroups defined by Lajos (1961), we introduce the concept of (m, n)-quasi-ideals of an ordered semigroup ( S , , ) as follows: let m, n be non-negative integers. A subsemigroup Q of S is called an (m, n)-quasi-ideal of S if it satisfies the following conditions: (i) (Q m S ]  ( SQ n ]  Q ;

i 1

Similarly,

i 1

it follows that

We will show that (1.1) holds. It is easy to see that

(

mn

n

Ai 

i I

i

A  Am SAn ] is an (m, n)-ideal containing A

mn i 1

[ A]( m , n )  (  Ai  Am SAn ].

(A

Then ( iI Ai ) S ( iI Ai )   iI Ai . Since

(

(

Finally, by

Ai )m S ( iI Ai )n  A mj SA nj  A j . m

i 1

of S, and

Proof. Let { Ai | i  I } be the set of all (m, n)-ideals contain-

iI

mn

 (  Ai  Am SAn ].

(1.1)

i 1

(

i 1

 ( Am SAn ]

Hence

[ A]( m, n )  (  Ai  Am SAn ]

SAn ]) m S ((  Ai  Am SAn ])n

i 1

Theorem 1.1. Let A be a non-empty subset of an ordered semigroup ( S , , ) . Then the intersection of all (m, n)-ideals containing A of S, denoted by [ A]( m , n ) , is an (m, n)-ideal containing A of S, and it is of the form m n

mn

m

m

n

0

0

Here, Q S  SQ  S. Note that every (m, n)-quasi-ideal of S is an (m, n)-ideal of S. It’s easy to see that if Q is a quasi-ideal of S, then Q is an (m, n)-quasi-ideal of S. The following example shows that an (m, n)-quasi-ideal of S needs not to be a quasi-ideal of S. Example 1.1. Let S  {a, b, c, d } be an ordered semigroup with the multiplication and the order relation defined by:

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L. Bussaban & T. Changphas / Songklanakarin J. Sci. Technol. 38 (2), 199-206, 2016

xy  (

max{ m , n }



Ai ]  (

max{ m , n}



i 1

Ai ]  (( Am S ]  (SAn ]).

i 1

If max{m, n}  j  k , then m, n  j  k , that is, ( A j  k ]  ( Am  ( j  k  m ) ]  ( Am S ] and ( A j  k ]  ( A( j  k  n )  n ]  ( SAn ]. Hence max{ m , n }

xy  ( A

j k

m

n

]  ( A S ]  ( SA ] 

(

 {(a, a ), (b, b), (c, c), (d , a), ( d , b ), (d , c), ( d , d )}.

i

] (( A S ]  (SA ]). m

A 

n

i 1

We give the covering relation and the figure of S by:

(

This shows that

  {(d , a ), (d , b), ( d , c )}

m n i 1

i

] (( A S ]  (SA ]) is a subsemim

A 

n

group of S. We now consider: max{ m , n }

(( 

A ]  (( A S ]  (SA i

m

n

]))

m

S

i 1

Let Q  {a, d } . For integers m, n > 1, we obtain that Q is an (m, n)-quasi-ideal of S but not a quasi-ideal of S. As in Theorem 1.1, we have the following. Theorem 1.2. Let ( S , , ) be an ordered semigroup. Then the intersection of all (m, n)-quasi-ideals containing a nonempty subset A of S, denoted by [ A]q ,( m , n ) , is an (m, n)-quasiideal containing A of S, and it is of the form

 ((

max{ m , n }



A ]  ( A S ]) S i

m

m

i 1

 ((

max{ m , n }



A ]  ( A S ]) i

m

max{ m , n }

m 1

(( 

i 1

 ((

A ]  ( A S ]) S i

m

i 1

max{ m , n }



A ]  ( A S ]) i

m

m 1

( AS ]

i 1

[ A]q ,( m, n )  (

max{ m , n}



Ai ]  (( Am S ]  (SAn ]). (1.2)

i 1

 ((

max{ m , n }



A ]  ( A S ]) i

m

max{ m , n }

m2

(( 

i 1

Proof. Let { Ai | i  I } be the set of all (m, n)-quasi-ideals



containing A of S. Then

i I

Ai is a subsemigroup contain-

 ((

n

i

i

i I

m



((

j

Ai ) S ]  (S ( iI Ai ) m

iI

i

i

n

] 

iI

and hence



i

iI

i I

Ai . Moreover,,

i I

(



i 1

m

i

A]

m

n

xy  ( A S ]  ( SA ]  ( Let x, y  ( i 1

max{ m , n }

i

]





where Q  (

max{ m  n } i 1

max{ m , n}

A ]  (( A S ]  ( SA i

m

n

]).

(( 

k

Ai ]  (( Am S ]  ( SAn ]), i

A

]  (( A S ]  (SA ]). Now,, m

n

Ai ]  (( Am S ]  ( SAn ])]

i 1

i 1

A ; then there exist j, k in {1, 2,  ,

max{m , n}} such that x  ( A j ] and y  ( A ]. If 1  j  k

 max{m, n} , then

max{ m , n}

 ( Am S ]  ( SAn ]

i 1

( SA ] , then max{ m , n }

n

(

n

n

2

Ai ]  (( Am S ]  (SAn ])) n  ( SAn ].

m

max{ m , n }

m



(Q S ]  (SQ ]

(( A S ]  ( SA ]) . If x  ( A S ]  ( SA ] or y  ( A S ]

m

( A S]

Then,

n

n

m2

i 1

A ]  (( A S ]  ( SA ])  . Let x, y  ( i 1 m

max{ m , n}

i

i I

Ai is an (m, n)-quasi-ideal of S.

i

m

m

S ((

Next, we will show that (1.2) holds. Clearly, max{ m , n}

i

 ( A S ]. Similarly,

( A ]   (A ]   A  ( A ] , i I

A ]  ( A S ])



n

S ]  ( S ( Aj ) ]  Aj,

iI

and then

m

i 1

(( A ) S ]  (S ( A ) ]  (( A ) m

i

i 1

max{ m , n }

ing A of S. For j  I , we have

A ]  ( A S ])( AS ]

 ((

max{ m , n}

 i 1

Ai ]]  ((( Am S ]  ( SAn ])]

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L. Bussaban & T. Changphas / Songklanakarin J. Sci. Technol. 38 (2), 199-206, 2016 max{ m , n }



( 

Ai ]  (( Am S ]  ( SAn ]).

we let

( B]A  { y  A∣y  b for some b  B}.

i 1

Thus

(

max{ m  n } i 1

A

i

]  (( A S ]  (SA ]) m

n

is an (m, n)-quasi-

It is clear that ( B ]A  ( B ] , and the equality holds in the following lemma.

ideal containing A of S, and [ A]q ,( m , n ) 

(

max{ m  n } i 1

Ai ]  (( A m S ]  ( SA n ]).

By max{ m , n}

( 

m , n} Ai ]  ([ A]q ,( m , n )  [ A]qmax{ ] ,( m , n )

i 1

Lemma 2.1. If A is an (m, n)-ideal of an ordered semigroup ( S , , ) , then ( B ] A  ( B ] for any non-empty subset B of A. Lemma 2.2. Let A be an (m, n)-ideal of an ordered semigroup ( S , , ) , and let   B  A . Then

 [ A]q ,( m , n )

(([ BA ]( m , n ) ) m S ([ BA ]( m , n ) ) n ]  ( B m SB n ]

and

m n

( A S ]  (SA ]  (([ A] m

n

) S] m

q ,( m , n )

where [ B A ]( m , n ) 

( B

i

 B m AB n ]A .

i 1

( S ([ A]q ,( m , n ) )

n

]  [ A]

q ,( m , n )

,

Proof. We have mn

(( B

it follows that max{ m , n}

( 

Ai ]  (( Am S ]  ( SAn ])  [ A]q ,( m ,n ) .

This shows that (1.2) holds, and the proof is completed.  For an element a of an ordered semigroup ( S , , ) , we write [{a}]q ,( m ,n ) (or simply [ a ]q ,( m ,n ) ) by max{ m , n}



 B m AB n ]mA S (  B i  B m AB n ]nA ]

i 1

i 1

mn

m n

i 1

i 1

mn

mn

i 1

i 1

 (((  B i  B m AB n )m S ( B i  B m AB n )n ]A ]

i 1

[ a ]q ,( m , n )  (

mn

i

 (((  B i  B m AB n )m S (  B i  B m AB n )n ]]

{a}i ]  ((a m S ]  (Sa n ]).

mn

m n

i 1

i 1

 ((  B i  B m AB n ) m S (  B i  B m AB n )n ].

i 1

In closing this section we quote the following two results proved by Sanborisoot et al. (2012).

m

Lemma 1.1. The following conditions hold for an ordered semigroup ( S , , ) and a  S : m m (1) ([ a]( m ,0 ) ) S  ( a S ] for any positive integer m. n n (2) S ([a ](0, n ) )  ( Sa ] for any positive integer n. m n m n (3) ([ a]( m , n ) ) S ([ a]( m , n ) )  ( a Sa ] for any positive integers m, n. Theorem 1.3. Let ( S , , ) be an ordered semigroup. Let m, n be positive integers. Let ( m ,0 ) be the set of all ( m, 0) -ideals of S, and let ( 0, n ) be the set of all (0, n)-ideals of S. Then the following conditions hold: (1) S is ( m, 0) -regular if and only if for all R  ( m ,0), R  (Rm S ] . (2) S is (0, n)-regular if and only if for all L  (0, n ) , L  ( SLn ] . 2. Main Results Let A be a subsemigroup of an ordered semigroup ( S , , ) . For a non-empty subset B of A,

n

m n Let x  (([ BA ]( m , n ) ) S ([ BA ]( m , n ) ) ] . Then x  y sz for

some s  S and y , z 

mn

mn

i 1

i 1

 B i  B m AB n . If y, z   B i ,

p

then y  B , z  B q for some p, q  {1, 2, , m  n}; hence m n

i m n x  ( B mp SB nq ]  ( B m SB n ]. If y   B , z  B SB , then i 1

mp y  B p for some p  {1, 2, , m  n} ; hence x  ( B S mn

i ( B m SB n ) n ]  ( B m SB n ]. If y  B m SB n , z   B , then i 1

z  B q for some q  {1, 2,  , m  n}; hence x  (( B m SB n ) m SB nq ]  ( B m SB n ] . Finally, if y , z  B m SB n , then x  (( B m SB n ) m S ( B m SB n ) n ]  ( B m SB n ] . This shows that

([ B

]

A ( m,n )

) S ([ B m

]

A ( m, n )

)

n

 ( B m SB n ].

By

( B m SB n ]  (([ BA ]( m, n ) ) m S ([ BA ]( m , n ) ) n ], it follows that

(([ BA ]( m , n ) ) m S ([ BA ]( m, n ) ) n ]  ( B m SB n ],

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L. Bussaban & T. Changphas / Songklanakarin J. Sci. Technol. 38 (2), 199-206, 2016



as required. This completes the proof.

Theorem 2.1. Let A be an (m, n)-ideal of an ordered semigroup ( S , , ) . Then every (m, n)-ideal of A is an (m, n)ideal of S if and only if for each non-empty subset B of A,

B m SB n  [ BA ]( m ,n ) m n

where [ BA ]( m , n ) 

( B

i

 B m AB n ]A .

Proof. Assume first that every (m, n)-ideal of A is an (m, n)ideal of S. Let   B  A. Since [ B A ]( m ,n ) is an (m, n)-ideal of A, it follows by assumption that [ B A ]( m , n ) is an (m, n)ideal of S. By Lemma 2.2, n

m

n

  {( a, b)}

(2.1)

i 1

m

 {(a, a ), ( a, b), (b, b), (c, c ), ( d , d )}. We give the covering relation and the figure of S by:

m

n

B SB  ( B SB ]  (([ BA ]( m , n ) ) S ([ BA ]( m ,n ) ) ]  ([ B A ]( m ,n ) ]  [ BA ]( m , n ) . Conversely, we assume that the equation (2.1) holds for any non-empty subset of A. Let C be an (m, n)-ideal of A. Then C  A and

C m SC n  (C  C 2   C m  n  C m AC n ] A  (C ] A  C . By Lemma 2.1, (C ]  C . Therefore, C is an (m, n)-ideal of S.  For m = 0, n = 1 (resp. m = 1, n = 0), we have the following corollary: Corollary 2.1. Let A be a left (resp. right) ideal of an ordered semigroup ( S , , ) . Then every left (resp. right) ideal of A is a left (resp. right) ideal of S if and only if for each non-empty subset B of A,

SB  ( B  AB ] A ( resp., BS  ( B  BA] A ). Moreover we have the following, taking m = 1, n = 1: Corollary 2.2. Let A be a bi-ideal of an ordered semigroup ( S , , ) . Then every bi-ideal of A is a bi-ideal of S if and only if for each non-empty subset B of A,

BSB  ( B  B 2  BAB ] A . Example 2.1. Let S  {a, b, c, d } be an ordered semigroup with the multiplication and the order relation defined by:

Then A  {a, d } is a bi-ideal of S, and {a} is a bi-ideal of A. It is easy to verify that, for each non-empty subset B of A, we have BSB  ( B  B 2  BAB ] A . Thus, by Corollary 2.2, {a} is a bi-ideal of S. Theorem 2.2. Let Q be an (m, n)-quasi-ideal of an ordered semigroup ( S , , ) . Then every (m, n)-quasi-ideal of Q is an (m, n)-quasi-ideal of S if and only if for each non-empty subset D of Q,

( D m S ]  ( SD n ]  [ DQ ]q ,( m , n ) where [ DQ ]q ,( m, n )  (

max{m , n }



(2.2)

D i ]Q  (( D mQ]Q  (QD n ]Q ).

i 1

Proof. Assume that every (m, n)-quasi-ideal of Q is an (m, n)-quasi-ideal of S. If D  Q is non-empty, then, by Theorem 1.2, [ DQ ]q ,( m , n ) is an (m, n)-quasi-ideal of Q. By assumption,

( D m S ]  ( SD n ]  (([ DQ ]q ,( m ,n ) ) m S ] ( S ([ DQ ]q ,( m , n ) ) n ]  [ DQ ]q ,( m , n ) . Conversely, we assume that the equation (2.2) holds for any non-empty subset of Q. Let C be an (m, n)-quasiideal of Q. Then C  Q and

(C m S ]  ( SC n ]  [CQ ]q ,( m , n )  C. By Lemma 2.1, (C ]  C . Therefore, C is an (m, n)-quasiideal of S.  For m = 1, n = 1, we have the following corollary: Corollary 2.3. Let Q be a quasi-ideal of an ordered semigroup ( S , , ) . Then every quasi-ideal of Q is a quasi-ideal of S if and only if for each non-empty subset D of Q,

( DS ]  ( SD ]  ( D ]Q  (( DQ ]Q  (QD ]Q ). Example 2.2. Let S  {a, b, c, d , f } be an ordered semigroup with the multiplication and the order relation defined by:

204

L. Bussaban & T. Changphas / Songklanakarin J. Sci. Technol. 38 (2), 199-206, 2016 It is easy to verify that Q  {a, b, d } is an (m, n)-quasi-ideal of S for any integers m, n  2, and the (m, n)-quasi-ideal of Q is {b, d } . For each non-empty subset C of Q, we have (C m S ]  ( SC n ]  [CQ ]q ,( m , n ). By Theorem 2.2, {b, d } is also a quasi-ideal of S. Let ( S , , ) be an ordered semigroup, and let m, n be non-negative integers. Then S is said to be (m, n)-regular (Sanborisoot et al., 2012), if for any a in S there exists x in m n m n S such that a  a xa , that is, if a  ( a Sa ] .

 {(a, a), (a, b), (a, c ), (a, d ), ( a, f ), (b, b), (c, c ), ( d , d ), ( f , f )}.

Example 2.4. Let S  {a, b, c, d } be an ordered semigroup with the multiplication and the order relation defined by:

We give the covering relation and the figure of S by:

  {( a, b), ( a, c ), ( a, d ), ( a, f )}

Then Q  {a, c, f } is a quasi-ideal of S, and the quasi-ideals of Q are D1  a , D2  a, c and D3  a, f  . For each non-empty subset C of Q, we have (CS ]  ( SC ]  (C ]Q  ((CQ ]Q  (QC ]Q ) . By Corollary 2.3, D1 , D2 , D3 are quasiideals of S. Example 2.3. Let S  {a, b, c, d , f } be an ordered semigroup with the multiplication and the order relation defined by:

 {( a, a ), ( a, b), (a, c), ( a, d ), (b, b), (c, c ), (c, d ), (d , d )}. We give the covering relation and the figure of S by:

  {( a, b), (a, c), (c, d )}

Then S is (m, n)-regular for any integer m, n  1 .

 {( a, a ), ( a, b), (a, c), ( a, f ), (b, b), (b, c ), (b, f ), (c, c ),

 d , d  ,  d , b  ,  d , c  ,  d , f  ,  f , f }. We give the covering relation and the figure of S by:

  {( a, b), (b, c), (b, f ), (d , b)}

Theorem 2.3. Let ( S , , ) be an ordered semigroup. Then S is (m, n)-regular if and only if

R  ( m ,0 ) , L  ( 0, n ) , R  L  ( R m Ln ]

(2.3)

where ( m ,0) is the set of all (m, 0)-ideals of S and ( 0, n ) is the set of all (0, n)-ideals of S. Proof. The assertion is obvious if m = 0, n = 0. If m = 0, n  0, we have to show that S is (0, n)-regular if and only if L  (0 ,n ) , L  ( SLn ] , and this follows by Theorem 1.3 (2). Similarly, for m  0, n = 0. This is obtained by Theorem 1.3 (1). Finally, we let m  0, n  0 . Assume that S is (m, n)regular. Let R  ( m ,0) and L  (0, n ) . We have ( R m Ln ]  R  L . Let a  R  L . Since S is regular, there exists x

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L. Bussaban & T. Changphas / Songklanakarin J. Sci. Technol. 38 (2), 199-206, 2016 m

n

in S such that a  a xa . We have m

a  a xa

m

n n

xa xa

n

a a

3 m 2

xa xa xa

n

n

nm  ( n 1)

Example 2.5. We consider the ordered semigroup which is defined in Example 2.2. We have  a 1,1   a  ,  b 1,1  a, b,  c (1,1)  a, c , d (1,1)  a, d , and  f (1,1)  a, f  .Then, by Theorem 2.4, S is regular..

n

L

References

 R m Ln  ( R m Ln ]. m

n

Thus R  L  ( R L ]. Conversely, we assume that (2.3) holds. Let a  S . Since [ a ]( m ,0)  ( m ,0) and S  ( 0, n ) , we have

[ a ]( m ,0 )  [a ]( m,0)  S  (([ a ]( m ,0) ) m S n ]  (([ a]( m ,0 ) ) m S ]. m

n

By Lemma 1.1, [ a ]( m ,0)  ( a S ] . Similarly, [ a ]( 0, n )  ( Sa ] . From

a  [ a ]( m ,0 )  [ a ](0, n )

 ( a m S ]  ( Sa n ]  (( a m S ]) m (( Sa n ]) n  ( a m S ]( Sa n ]  ( a m Sa n ], we conclude that S is (m, n)-regular. We now complete the proof. Corollary 2.4. Let ( S , , ) be an ordered semigroup. Then S is (m, n)-regular if and only if

a  S ,[ a ]( m ,0)  [ a]( 0,n )  (([a ]( m,0) ) m ([ a](0, n ) ) n ]. Theorem 2.4. Let ( S , , ) be an ordered semigroup. Then S is (m, n)-regular if and only if

a  S ,[ a ]( m , n )  ( a m Sa n ]. Proof. Assume that S is (m, n)-regular. Let a  S and x  [ a ]( m , n ) . Then, by Theorem 1.1, x  y for some y in m n

i 1

m

n

n

 a nm ( n 1) ( xa n ) n

i

n

Conversely, if a  S , then a  [a ]( m ,n )  ( a Sa ], and hence S is (m, n)-regular.



a

m

m

2 m 1

R

n

Since ( a Sa ]  [ a]( m , n ) ,[a ]( m, n )  (a Sa ].

n

 a Sa . If y  a m Sa n , we are done. Suppose that

mn

y   a i ; then y  a p for some p  {1, 2, , m  n} . We i 1

have

x  ( a p ]  (( a m Sa n ] p ]  (( a m Sa n ]]  ( a m Sa n ].

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