BARTON COLLEGE. PRACTICE PLACEMENT TEST. PAGE 1 OF 12. 1. Simplify:
3. 20 4 ( 8). + ÷ a) 4 b) ‐4 c) 12 d) ‐10.5. 2. Simplify: (2a – 4) + 2(a – 5) – 3(a+1).
BARTON COLLEGE PRACTICE PLACEMENT TEST 3 1. Simplify: 20 + 4 ÷ (!8) a) 4 b) ‐4 c) 12 d) ‐10.5 2. Simplify: (2a – 4) + 2(a – 5) – 3(a+1) a) 7a – 11 b) a – 17 c) a – 11 d) 7a ‐17 3. Evaluate the expression: 4a 2 ! 4ab + b 2 , when a = 2 and b = 5 a) ‐14 b) 1 c) 66 d) 81 4. Firefighters use the formula S = 0.5P + 26 to compute the horizontal range S in feet of water from a particular hose, where P is the nozzle pressure in pounds. Find the horizontal range if pressure is 90 lb. a) 44 feet b) 450 feet c) 19 feet d) 71 feet 3
(
)
5. Simplify:
2 x 2 !3 x 2
a) 54x12
b) 18x8
d) !54x8
16w2u10 v4
d)
c) 5.6 " 10!5
d) 5.6 " 10!7
c) 120000
d) 12000
c) !18x12
c)
!2
6. Simplify: a)
w2 v 4 4u 7
" 2u !5v 2 # $ % & 8w '
b)
16v 4 w2u10
7. Express in scientific notation: 0. 0000056 a) 5.6 " 10!6 b) 5.6 ! 106 8. Expand: 1.20 ! 105 a) 12000000 b) 1200000
PAGE 1 OF 12
u 7v 4 4 w2
BARTON COLLEGE PRACTICE PLACEMENT TEST
1 5 3 x! = 4 8 8
9. Solve: a) x = 4
10. Solve: a) x = 9
c) x=
1 2
d) x =
mv 2 r
F rv 2
12. Solve P:
b) x = 28
c) x = ‐8
d) x = ‐18
b) m = Frv 2
c) m =
Fv 2 r
d) m =
Fr v2
A ! rt 2
c) P =
A 1 + rt
d) P =
A 2rt
d) x = 2
d) x = ! , !
A = P + Pr t
a) P = A ! rt
b) P =
13. Solve:
1 4
8(x – 2) – 5(x + 4) = 20 + x
11. Solve for m: F = a) m =
b) x = 2
6 4 = x !5 x
a) x = ‐5 14. Solve: 2 x ! 3 = 5 a) x = 4, 0
b) x = ‐6
b) x =
1 11 , 2 2
c) x = ‐10
c) x = 0,
11 2
1 2
15. Solve: 3 ! a) x = 4 16. Simplify: a) x – 2y
x 4 = x!4 4! x
b) x = ‐4
c) x = 1
d) No solution
b) x(x + 3y)
c) x(x‐2y)
d) x + 3y
x3 + x 2 y ! 6 xy 2 x 2 ! 2 xy
PAGE 2 OF 12
11 2
BARTON COLLEGE PRACTICE PLACEMENT TEST
2
17. Simplify:
4x !1 2 x2 + 5x ! 3
a) Cannot be simplified 18. Solve: ‐3(2x – 3) ≤ 27 a) x ≤ ‐6 19. Solve:
